Skip to main content

五、场论初步

小题

  1. 【1989-12-3 分】u=xy2i+yezj+xln(1+z2)k\displaystyle \vec{u}=xy^{2}\vec{i}+ye^{z}\vec{j}+x\ln(1+z^{2})\vec{k}P(1,1,0)\displaystyle P(1,1,0)divu=\displaystyle \operatorname{div}\vec{u}=

  2. **【1993-12-3 分】**设 u=lnx2+y2+z2\displaystyle u=\ln\sqrt{x^{2}+y^{2}+z^{2}},则div(grad u)=\displaystyle \operatorname{div}(\operatorname{grad}\ u)=

  3. 【2001-1-3 分】r=x2+y2+z2\displaystyle r=\sqrt{x^{2}+y^{2}+z^{2}},则div(grad r)(1,2,2)=\displaystyle \operatorname{div}(\operatorname{grad}\ r)\big|_{(1,-2,2)}=

  4. 【2016-1-4 分】A=(x+y+z)i+xyj+zk\displaystyle \vec{A}=(x+y+z)\vec{i}+xy\vec{j}+z\vec{k},求rotA\displaystyle \operatorname{rot}\vec{A}

  5. 【2018-1-4 分】F=xyiyzj+zxk\displaystyle \vec{F}=xy\vec{i}-yz\vec{j}+zx\vec{k},则rotF(1,1,0)=\displaystyle \operatorname{rot}\vec{F}(1,1,0)=