On this page
基础部分
n n n 维向量组α 1 , α 2 , ⋯ , α r ( 3 ≤ r ≤ n ) \alpha_1,\alpha_2,\cdots,\alpha_r(3\leq r\leq n) α 1 , α 2 , ⋯ , α r ( 3 ≤ r ≤ n ) 线性相关的充分必要条件是( ).
A. 对于任意一组不全为零的数k 1 , k 2 , ⋯ , k r k_1,k_2,\cdots,k_r k 1 , k 2 , ⋯ , k r 都有k 1 α 1 + k 2 α 2 + ⋯ + k r α r = 0 k_1\alpha_1+k_2\alpha_2+\cdots+k_r\alpha_r=0 k 1 α 1 + k 2 α 2 + ⋯ + k r α r = 0
B. α 1 , α 2 , ⋯ , α r \alpha_1,\alpha_2,\cdots,\alpha_r α 1 , α 2 , ⋯ , α r 中任意两个向量都线性相关
C. α 1 , α 2 , ⋯ , α r \alpha_1,\alpha_2,\cdots,\alpha_r α 1 , α 2 , ⋯ , α r 中任何一个向量都能由其余向量线性表示
D. α 1 , α 2 , ⋯ , α r \alpha_1,\alpha_2,\cdots,\alpha_r α 1 , α 2 , ⋯ , α r 中至少有一个向量能由其余向量线性表示
设n n n 阶方阵A = [ α 1 , α 2 , ⋯ , α n ] A=[\alpha_1,\alpha_2,\cdots,\alpha_n] A = [ α 1 , α 2 , ⋯ , α n ] ,B = [ β 1 , β 2 , ⋯ , β n ] B=[\beta_1,\beta_2,\cdots,\beta_n] B = [ β 1 , β 2 , ⋯ , β n ] ,A B = [ γ 1 , γ 2 , ⋯ , γ n ] AB=[\gamma_1,\gamma_2,\cdots,\gamma_n] A B = [ γ 1 , γ 2 , ⋯ , γ n ] ,记向量组I : α 1 , α 2 , ⋯ , α n I:\alpha_1,\alpha_2,\cdots,\alpha_n I : α 1 , α 2 , ⋯ , α n ,向量组I I : β 1 , β 2 , ⋯ , β n II:\beta_1,\beta_2,\cdots,\beta_n I I : β 1 , β 2 , ⋯ , β n ,向量组I I I : γ 1 , γ 2 , ⋯ , γ n III:\gamma_1,\gamma_2,\cdots,\gamma_n I I I : γ 1 , γ 2 , ⋯ , γ n ,如果向量组I I I III I I I 线性相关,则( )
A. 向量组I I I 线性相关 B. 向量组I I II I I 线性相关 C. 向量组I I I 与I I II I I 都线性相关 D. 向量组I I I 与I I II I I 至少有一个线性相关
设α 1 , α 2 , ⋯ , α n \alpha_1,\alpha_2,\cdots,\alpha_n α 1 , α 2 , ⋯ , α n 是n n n 个n n n 维的线性无关向量,α n + 1 = k 1 α 1 + k 2 α 2 + ⋯ + k n α n \alpha_{n+1}=k_1\alpha_1+k_2\alpha_2+\cdots+k_n\alpha_n α n + 1 = k 1 α 1 + k 2 α 2 + ⋯ + k n α n ,其中k 1 , k 2 , ⋯ , k n k_1,k_2,\cdots,k_n k 1 , k 2 , ⋯ , k n 全不为0,则下列结论:①α 2 , α 3 , ⋯ , α n + 1 \alpha_2,\alpha_3,\cdots,\alpha_{n+1} α 2 , α 3 , ⋯ , α n + 1 线性相关;②α 1 , α 3 , ⋯ , α n + 1 \alpha_1,\alpha_3,\cdots,\alpha_{n+1} α 1 , α 3 , ⋯ , α n + 1 线性相关;③α 1 , α 2 , α 4 , ⋯ , α n + 1 \alpha_1,\alpha_2,\alpha_4,\cdots,\alpha_{n+1} α 1 , α 2 , α 4 , ⋯ , α n + 1 线性相关.正确的个数为( ).
A. 0 B. 1 C. 2 D. 3
设A = [ a 11 a 12 a 13 a 14 a 21 a 22 a 23 a 24 a 31 a 32 a 33 a 34 ] A=\begin{bmatrix}a_{11}&a_{12}&a_{13}&a_{14}\\a_{21}&a_{22}&a_{23}&a_{24}\\a_{31}&a_{32}&a_{33}&a_{34}\end{bmatrix} A = a 11 a 21 a 31 a 12 a 22 a 32 a 13 a 23 a 33 a 14 a 24 a 34 ,A A A 分别以列和行分块,记为A = [ α 1 , α 2 , α 3 , α 4 ] = [ β 1 β 2 β 3 ] A=[\alpha_1,\alpha_2,\alpha_3,\alpha_4]=\begin{bmatrix}\beta_1\\\beta_2\\\beta_3\end{bmatrix} A = [ α 1 , α 2 , α 3 , α 4 ] = β 1 β 2 β 3 ,其中∣ a 12 a 14 a 32 a 34 ∣ ≠ 0 \begin{vmatrix}a_{12}&a_{14}\\a_{32}&a_{34}\end{vmatrix}\neq0 a 12 a 32 a 14 a 34 = 0 ,∣ a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33 ∣ = 0 \begin{vmatrix}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\a_{31}&a_{32}&a_{33}\end{vmatrix}=0 a 11 a 21 a 31 a 12 a 22 a 32 a 13 a 23 a 33 = 0 ,则以下结论中:①r ( A ) = 2 r(A)=2 r ( A ) = 2 ;②α 2 , α 4 \alpha_2,\alpha_4 α 2 , α 4 线性无关;③β 1 , β 2 , β 3 \beta_1,\beta_2,\beta_3 β 1 , β 2 , β 3 线性相关;④α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性相关.所有正确结论的序号是( ).
A. ①③ B. ②③ C. ①④ D. ②④
设向量组α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性无关,若向量β 1 \beta_1 β 1 可由α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性表示,向量β 2 \beta_2 β 2 不能由α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性表示,则必有( ).
A. 向量组α 1 , α 2 , β 1 \alpha_1,\alpha_2,\beta_1 α 1 , α 2 , β 1 线性相关 B. 向量组α 1 , α 2 , β 1 \alpha_1,\alpha_2,\beta_1 α 1 , α 2 , β 1 线性无关 C. 向量组α 1 , α 2 , β 2 \alpha_1,\alpha_2,\beta_2 α 1 , α 2 , β 2 线性相关 D. 向量组α 1 , α 2 , β 2 \alpha_1,\alpha_2,\beta_2 α 1 , α 2 , β 2 线性无关
设x 1 = [ 1 , 2 , 2 , − 4 ] T x_1=[1,2,2,-4]^T x 1 = [ 1 , 2 , 2 , − 4 ] T ,x 2 = [ 1 , k , − 1 , − 4 ] T x_2=[1,k,-1,-4]^T x 2 = [ 1 , k , − 1 , − 4 ] T ,x 3 = [ − 1 , − 3 , 1 , k + 6 ] T x_3=[-1,-3,1,k+6]^T x 3 = [ − 1 , − 3 , 1 , k + 6 ] T ,则( ).
A. 对任意常数k k k ,x 1 , x 2 , x 3 x_1,x_2,x_3 x 1 , x 2 , x 3 线性无关 B. 当k = 3 k=3 k = 3 时,x 1 , x 2 , x 3 x_1,x_2,x_3 x 1 , x 2 , x 3 线性相关 C. 当k = − 2 k=-2 k = − 2 时,x 1 , x 2 , x 3 x_1,x_2,x_3 x 1 , x 2 , x 3 线性相关 D. k ≠ 3 k\neq3 k = 3 且k ≠ − 2 k\neq-2 k = − 2 是x 1 , x 2 , x 3 x_1,x_2,x_3 x 1 , x 2 , x 3 线性无关的充要条件
设α 1 = [ 1 , 1 , 0 , − 2 ] T \alpha_1=[1,1,0,-2]^T α 1 = [ 1 , 1 , 0 , − 2 ] T ,α 2 = [ 1 , k , − 2 , 0 ] T \alpha_2=[1,k,-2,0]^T α 2 = [ 1 , k , − 2 , 0 ] T ,α 3 = [ − 1 , − 3 , 2 , k + 4 ] T \alpha_3=[-1,-3,2,k+4]^T α 3 = [ − 1 , − 3 , 2 , k + 4 ] T ,则( ).
A. 对任意常数k k k ,α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性无关 B. 当k = 3 k=3 k = 3 时,α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性相关 C. 当k = − 4 k=-4 k = − 4 时,α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性相关 D. k ≠ 3 k\neq3 k = 3 且k ≠ − 4 k\neq-4 k = − 4 是α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性无关的充要条件
已知向量组α , β , γ \alpha,\beta,\gamma α , β , γ 线性无关,则k ≠ 1 k\neq1 k = 1 是向量组α + k β \alpha+k\beta α + k β ,β + k γ \beta+k\gamma β + k γ ,α − γ \alpha-\gamma α − γ 线性无关的( ).
A. 充分必要条件 B. 充分非必要条件 C. 必要非充分条件 D. 既非充分又非必要条件
若向量组α 1 = [ 1 , 0 , 2 , a ] T \alpha_1=[1,0,2,a]^T α 1 = [ 1 , 0 , 2 , a ] T ,α 2 = [ 2 , 1 , a , 4 ] T \alpha_2=[2,1,a,4]^T α 2 = [ 2 , 1 , a , 4 ] T ,α 3 = [ 0 , a , 5 , − 6 ] T \alpha_3=[0,a,5,-6]^T α 3 = [ 0 , a , 5 , − 6 ] T 线性相关,则a = a= a = ( )
A. -1 B. 3 C. -3 D. 5
n n n 维向量组α 1 , α 2 , ⋯ , α s \alpha_1,\alpha_2,\cdots,\alpha_s α 1 , α 2 , ⋯ , α s 线性无关,β = k 1 α 1 + k 2 α 2 + ⋯ + k s α s \beta=k_1\alpha_1+k_2\alpha_2+\cdots+k_s\alpha_s β = k 1 α 1 + k 2 α 2 + ⋯ + k s α s ,其中k 1 , k 2 , ⋯ , k s k_1,k_2,\cdots,k_s k 1 , k 2 , ⋯ , k s 全不为零,则( ).
A. 向量组α 1 , α 2 , ⋯ , α s − 1 , β \alpha_1,\alpha_2,\cdots,\alpha_{s-1},\beta α 1 , α 2 , ⋯ , α s − 1 , β 线性相关 B. 向量组α 1 , α 2 , ⋯ , α s , β \alpha_1,\alpha_2,\cdots,\alpha_s,\beta α 1 , α 2 , ⋯ , α s , β 线性无关 C. 向量组α 2 , α 3 , ⋯ , α s , β \alpha_2,\alpha_3,\cdots,\alpha_s,\beta α 2 , α 3 , ⋯ , α s , β 线性相关 D. 向量组α 1 , ⋯ , α i − 1 , β ; α i + 1 , ⋯ , α s \alpha_1,\cdots,\alpha_{i-1},\beta;\alpha_{i+1},\cdots,\alpha_s α 1 , ⋯ , α i − 1 , β ; α i + 1 , ⋯ , α s 线性无关
设向量α 1 = [ 1 , 1 , 2 ] T \alpha_1=[1,1,2]^T α 1 = [ 1 , 1 , 2 ] T ,α 2 = [ 2 , a , 4 ] T \alpha_2=[2,a,4]^T α 2 = [ 2 , a , 4 ] T ,α 3 = [ a , 3 , 6 ] T \alpha_3=[a,3,6]^T α 3 = [ a , 3 , 6 ] T ,α 4 = [ 0 , 2 , 2 a ] T \alpha_4=[0,2,2a]^T α 4 = [ 0 , 2 , 2 a ] T ,若向量组α 1 , α 2 , α 3 , α 4 \alpha_1,\alpha_2,\alpha_3,\alpha_4 α 1 , α 2 , α 3 , α 4 与α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 不等价,则a = a= a = ( )
A. 2 B. 3 C. 4 D. 6
已知向量组α 1 = [ 1 , 2 , − 3 ] T \alpha_1=[1,2,-3]^T α 1 = [ 1 , 2 , − 3 ] T ,α 2 = [ 3 , 0 , − 3 ] T \alpha_2=[3,0,-3]^T α 2 = [ 3 , 0 , − 3 ] T ,α 3 = [ 9 , 6 , − 15 ] T \alpha_3=[9,6,-15]^T α 3 = [ 9 , 6 , − 15 ] T 与向量组β 1 = [ 0 , 1 , − 1 ] T \beta_1=[0,1,-1]^T β 1 = [ 0 , 1 , − 1 ] T ,β 2 = [ 3 , a , 1 ] T \beta_2=[3,a,1]^T β 2 = [ 3 , a , 1 ] T ,β 3 = [ 1 , 1 , b ] T \beta_3=[1,1,b]^T β 3 = [ 1 , 1 , b ] T 等价,则a , b a,b a , b 的值分别为( ).
A. -4,2 B. 4,-2 C. -4,2 D. 4,2
设α 1 = [ 1 1 0 ] \alpha_1=\begin{bmatrix}1\\1\\0\end{bmatrix} α 1 = 1 1 0 ,α 2 = [ 1 0 1 ] \alpha_2=\begin{bmatrix}1\\0\\1\end{bmatrix} α 2 = 1 0 1 ,α 3 = [ − 1 0 0 ] \alpha_3=\begin{bmatrix}-1\\0\\0\end{bmatrix} α 3 = − 1 0 0 ,记β 1 = α 1 \beta_1=\alpha_1 β 1 = α 1 ,β 2 = α 2 − k 1 β 1 \beta_2=\alpha_2-k_1\beta_1 β 2 = α 2 − k 1 β 1 ,β 3 = α 3 − k 2 β 1 − k 3 β 2 \beta_3=\alpha_3-k_2\beta_1-k_3\beta_2 β 3 = α 3 − k 2 β 1 − k 3 β 2 ,若β 1 , β 2 , β 3 \beta_1,\beta_2,\beta_3 β 1 , β 2 , β 3 为正交向量组,则k 1 , k 2 , k 3 k_1,k_2,k_3 k 1 , k 2 , k 3 依次为( ).
A. − 1 2 , 1 2 , − 1 3 -\frac{1}{2},\frac{1}{2},-\frac{1}{3} − 2 1 , 2 1 , − 3 1 B. − 1 2 , 1 2 , 1 3 -\frac{1}{2},\frac{1}{2},\frac{1}{3} − 2 1 , 2 1 , 3 1 C. 1 2 , 1 2 , 1 3 \frac{1}{2},\frac{1}{2},\frac{1}{3} 2 1 , 2 1 , 3 1 D. 1 2 , − 1 2 , − 1 3 \frac{1}{2},-\frac{1}{2},-\frac{1}{3} 2 1 , − 2 1 , − 3 1
设向量组α 1 = [ 1 0 − 1 ] \alpha_1=\begin{bmatrix}1\\0\\-1\end{bmatrix} α 1 = 1 0 − 1 ,α 2 = [ a 1 1 ] \alpha_2=\begin{bmatrix}a\\1\\1\end{bmatrix} α 2 = a 1 1 ,α 3 = [ 2 1 1 ] \alpha_3=\begin{bmatrix}2\\1\\1\end{bmatrix} α 3 = 2 1 1 不可由向量组β 1 = [ 1 1 2 ] \beta_1=\begin{bmatrix}1\\1\\2\end{bmatrix} β 1 = 1 1 2 ,β 2 = [ 2 3 7 ] \beta_2=\begin{bmatrix}2\\3\\7\end{bmatrix} β 2 = 2 3 7 ,β 3 = [ a 0 − a ] \beta_3=\begin{bmatrix}a\\0\\-a\end{bmatrix} β 3 = a 0 − a 线性表示,则a a a 的取值范围为
设R 3 R^3 R 3 中的两个基:α 1 = [ 1 1 1 ] \alpha_1=\begin{bmatrix}1\\1\\1\end{bmatrix} α 1 = 1 1 1 ,α 2 = [ 1 2 1 ] \alpha_2=\begin{bmatrix}1\\2\\1\end{bmatrix} α 2 = 1 2 1 ,α 3 = [ 2 − 1 − 1 ] \alpha_3=\begin{bmatrix}2\\-1\\-1\end{bmatrix} α 3 = 2 − 1 − 1 ;β 1 = [ 1 2 − 1 ] \beta_1=\begin{bmatrix}1\\2\\-1\end{bmatrix} β 1 = 1 2 − 1 ,β 2 = [ 2 2 − 1 ] \beta_2=\begin{bmatrix}2\\2\\-1\end{bmatrix} β 2 = 2 2 − 1 ,β 3 = [ 2 − 1 − 1 ] \beta_3=\begin{bmatrix}2\\-1\\-1\end{bmatrix} β 3 = 2 − 1 − 1 .由α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 到β 1 , β 2 , β 3 \beta_1,\beta_2,\beta_3 β 1 , β 2 , β 3 的过渡矩阵为
强化部分
设α 1 , α 2 , ⋯ , α s \alpha_1,\alpha_2,\cdots,\alpha_s α 1 , α 2 , ⋯ , α s 是n n n 维列向量,A A A 是m × n m\times n m × n 矩阵,记向量组( I ) (I) ( I ) 为α 1 , α 2 , ⋯ , α s \alpha_1,\alpha_2,\cdots,\alpha_s α 1 , α 2 , ⋯ , α s ,向量组( I I ) (II) ( I I ) 为A α 1 , A α 2 , ⋯ , A α s A\alpha_1,A\alpha_2,\cdots,A\alpha_s A α 1 , A α 2 , ⋯ , A α s ,则下列命题正确的是( ).
A. 若向量组( I ) (I) ( I ) 线性无关,则向量组( I I ) (II) ( I I ) 线性无关 B. 若向量组( I I ) (II) ( I I ) 线性无关,则向量组( I ) (I) ( I ) 线性无关 C. 若向量组( I I ) (II) ( I I ) 线性相关,则向量组( I ) (I) ( I ) 线性相关 D. 向量组( I ) (I) ( I ) 与向量组( I I ) (II) ( I I ) 具有不同的线性相关性
设A = [ a 1 1 1 a a 1 1 a ] A=\begin{bmatrix}a&1&1\\1&a&a\\1&1&a\end{bmatrix} A = a 1 1 1 a 1 1 a a 可经初等列变换化成B = [ a 1 1 1 a 1 1 1 a ] B=\begin{bmatrix}a&1&1\\1&a&1\\1&1&a\end{bmatrix} B = a 1 1 1 a 1 1 1 a ,则a a a 的取值范围为( ).
A. { a ∣ a ∈ R , a ≠ − 2 } \{a|a\in R,a\neq-2\} { a ∣ a ∈ R , a = − 2 } B. { a ∣ a ∈ R , a ≠ − 2 , a ≠ − 1 } \{a|a\in R,a\neq-2,a\neq-1\} { a ∣ a ∈ R , a = − 2 , a = − 1 } C. { a ∣ a ∈ R , a ≠ 1 , a ≠ − 1 } \{a|a\in R,a\neq1,a\neq-1\} { a ∣ a ∈ R , a = 1 , a = − 1 } D. { a ∣ a ∈ R , a ≠ − 1 } \{a|a\in R,a\neq-1\} { a ∣ a ∈ R , a = − 1 }
设3维向量组α 1 = [ 1 , 1 , 0 ] T \alpha_1=[1,1,0]^T α 1 = [ 1 , 1 , 0 ] T ,α 2 = [ 5 , 3 , 2 ] T \alpha_2=[5,3,2]^T α 2 = [ 5 , 3 , 2 ] T ,α 3 = [ 1 , 3 , − 1 ] T \alpha_3=[1,3,-1]^T α 3 = [ 1 , 3 , − 1 ] T ,α 4 = [ − 2 , 2 , − 3 ] T \alpha_4=[-2,2,-3]^T α 4 = [ − 2 , 2 , − 3 ] T ,且A A A 是3阶矩阵,满足A α 1 = α 2 A\alpha_1=\alpha_2 A α 1 = α 2 ,A α 2 = α 3 A\alpha_2=\alpha_3 A α 2 = α 3 ,A α 3 = α 4 A\alpha_3=\alpha_4 A α 3 = α 4 ,则A α 4 = A\alpha_4= A α 4 =
已知[ 1 1 1 1 2 1 1 1 1 ] = [ 1 1 1 2 1 1 ] A \begin{bmatrix}1&1&1\\1&2&1\\1&1&1\end{bmatrix}=\begin{bmatrix}1&1\\1&2\\1&1\end{bmatrix}A 1 1 1 1 2 1 1 1 1 = 1 1 1 1 2 1 A ,则A = A= A = ( )
A. [ 1 0 1 0 1 0 ] \begin{bmatrix}1&0&1\\0&1&0\end{bmatrix} [ 1 0 0 1 1 0 ] B. [ 0 1 0 1 0 1 ] \begin{bmatrix}0&1&0\\1&0&1\end{bmatrix} [ 0 1 1 0 0 1 ] C. [ 1 1 0 0 0 1 ] \begin{bmatrix}1&1&0\\0&0&1\end{bmatrix} [ 1 0 1 0 0 1 ] D. [ 1 0 1 0 0 1 ] \begin{bmatrix}1&0&1\\0&0&1\end{bmatrix} [ 1 0 0 0 1 1 ]
设α 1 = [ 1 − 1 1 ] \alpha_1=\begin{bmatrix}1\\-1\\1\end{bmatrix} α 1 = 1 − 1 1 ,α 2 = [ 1 1 0 ] \alpha_2=\begin{bmatrix}1\\1\\0\end{bmatrix} α 2 = 1 1 0 ,α 3 = [ 2 0 1 ] \alpha_3=\begin{bmatrix}2\\0\\1\end{bmatrix} α 3 = 2 0 1 ;β 1 = [ a − 1 1 ] \beta_1=\begin{bmatrix}a\\-1\\1\end{bmatrix} β 1 = a − 1 1 ,β 2 = [ 4 0 b ] \beta_2=\begin{bmatrix}4\\0\\b\end{bmatrix} β 2 = 4 0 b ,β 3 = [ 0 c 1 ] \beta_3=\begin{bmatrix}0\\c\\1\end{bmatrix} β 3 = 0 c 1 ,问a , b , c a,b,c a , b , c 为何值时,向量组α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 与β 1 , β 2 , β 3 \beta_1,\beta_2,\beta_3 β 1 , β 2 , β 3 等价,且当向量组等价时,求β 1 \beta_1 β 1 由α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 的线性表示式及α 1 \alpha_1 α 1 由β 1 , β 2 , β 3 \beta_1,\beta_2,\beta_3 β 1 , β 2 , β 3 的线性表示式.
设α 1 = [ 1 0 1 ] \alpha_1=\begin{bmatrix}1\\0\\1\end{bmatrix} α 1 = 1 0 1 ,α 2 = [ 1 1 2 ] \alpha_2=\begin{bmatrix}1\\1\\2\end{bmatrix} α 2 = 1 1 2 ,α 3 = [ 1 2 a ] \alpha_3=\begin{bmatrix}1\\2\\a\end{bmatrix} α 3 = 1 2 a ,β 1 = [ − 1 2 1 ] \beta_1=\begin{bmatrix}-1\\2\\1\end{bmatrix} β 1 = − 1 2 1 ,β 2 = [ 1 0 b ] \beta_2=\begin{bmatrix}1\\0\\b\end{bmatrix} β 2 = 1 0 b ,A = [ α 1 , α 2 , α 3 ] A=[\alpha_1,\alpha_2,\alpha_3] A = [ α 1 , α 2 , α 3 ] ,B = [ β 1 , β 2 ] B=[\beta_1,\beta_2] B = [ β 1 , β 2 ] .
(1)a , b a,b a , b 为何值时,β 1 , β 2 \beta_1,\beta_2 β 1 , β 2 能同时由α 1 , α 2 , α 3 \alpha_1,\alpha_2,\alpha_3 α 1 , α 2 , α 3 线性表示?若能表示,写出其表示式;
(2)a , b a,b a , b 为何值时,矩阵方程A X = B AX=B A X = B 有解?若有解,求出其全部解.
设3维列向量α 1 , α 2 \alpha_1,\alpha_2 α 1 , α 2 线性无关,β 1 , β 2 \beta_1,\beta_2 β 1 , β 2 线性无关.
(1) 证明:存在3维非零列向量ξ \xi ξ ,ξ \xi ξ 既可由α 1 , α 2 \alpha_1,\alpha_2 α 1 , α 2 线性表示,也可由β 1 , β 2 \beta_1,\beta_2 β 1 , β 2 线性表示;
(2)若α 1 = [ 1 , − 2 , 3 ] T \alpha_1=[1,-2,3]^T α 1 = [ 1 , − 2 , 3 ] T ,α 2 = [ 2 , 1 , 1 ] T \alpha_2=[2,1,1]^T α 2 = [ 2 , 1 , 1 ] T ,β 1 = [ − 2 , 1 , 4 ] T \beta_1=[-2,1,4]^T β 1 = [ − 2 , 1 , 4 ] T ,β 2 = [ − 5 , − 3 , 5 ] T \beta_2=[-5,-3,5]^T β 2 = [ − 5 , − 3 , 5 ] T ,求既可由α 1 , α 2 \alpha_1,\alpha_2 α 1 , α 2 线性表示,也可由β 1 , β 2 \beta_1,\beta_2 β 1 , β 2 线性表示的所有非零列向量ξ \xi ξ
设向量空间V V V 满足x 1 + x 2 + x 3 = 0 x_1+x_2+x_3=0 x 1 + x 2 + x 3 = 0 ,− ∞ < x i < + ∞ , i = 1 , 2 , 3 -\infty<x_i<+\infty,i=1,2,3 − ∞ < x i < + ∞ , i = 1 , 2 , 3 ,则V V V 的一个基为( ).
A. [ − 1 0 1 ] , [ − 1 1 0 ] , [ 1 1 1 ] \begin{bmatrix}-1\\0\\1\end{bmatrix},\begin{bmatrix}-1\\1\\0\end{bmatrix},\begin{bmatrix}1\\1\\1\end{bmatrix} − 1 0 1 , − 1 1 0 , 1 1 1 B. [ 1 0 − 1 ] , [ − 1 − 1 0 ] \begin{bmatrix}1\\0\\-1\end{bmatrix},\begin{bmatrix}-1\\-1\\0\end{bmatrix} 1 0 − 1 , − 1 − 1 0 C. [ 1 0 − 1 ] , [ − 1 − 1 0 ] , [ 1 1 1 ] \begin{bmatrix}1\\0\\-1\end{bmatrix},\begin{bmatrix}-1\\-1\\0\end{bmatrix},\begin{bmatrix}1\\1\\1\end{bmatrix} 1 0 − 1 , − 1 − 1 0 , 1 1 1 D. [ − 1 0 1 ] , [ − 1 1 0 ] \begin{bmatrix}-1\\0\\1\end{bmatrix},\begin{bmatrix}-1\\1\\0\end{bmatrix} − 1 0 1 , − 1 1 0
向量空间V = { ( x , y , z ) ∣ ( x , y , z ) ∈ R 3 , x − 2 z = 0 } V=\{(x,y,z)|(x,y,z)\in R^3,x-2z=0\} V = {( x , y , z ) ∣ ( x , y , z ) ∈ R 3 , x − 2 z = 0 } 的一个基为
设β 1 , β 2 , β 3 \beta_1,\beta_2,\beta_3 β 1 , β 2 , β 3 是3维向量空间R 3 R^3 R 3 的一个基,则基β 1 , 2 β 2 , 3 β 3 \beta_1,2\beta_2,3\beta_3 β 1 , 2 β 2 , 3 β 3 到基β 1 − β 2 , β 2 + β 3 , β 3 − β 1 \beta_1-\beta_2,\beta_2+\beta_3,\beta_3-\beta_1 β 1 − β 2 , β 2 + β 3 , β 3 − β 1 的过渡矩阵为( ).
A. [ 0 − 2 1 3 0 − 6 − 8 4 0 ] \begin{bmatrix}0&-2&1\\3&0&-6\\-8&4&0\end{bmatrix} 0 3 − 8 − 2 0 4 1 − 6 0 B. [ 1 0 − 1 − 1 2 1 2 0 0 1 3 1 3 ] \begin{bmatrix}1&0&-1\\-\frac{1}{2}&\frac{1}{2}&0\\0&\frac{1}{3}&\frac{1}{3}\end{bmatrix} 1 − 2 1 0 0 2 1 3 1 − 1 0 3 1 C. [ 1 2 − 1 3 1 4 0 1 2 − 1 3 − 1 3 0 1 4 ] \begin{bmatrix}\frac{1}{2}&-\frac{1}{3}&\frac{1}{4}\\0&\frac{1}{2}&-\frac{1}{3}\\-\frac{1}{3}&0&\frac{1}{4}\end{bmatrix} 2 1 0 − 3 1 − 3 1 2 1 0 4 1 − 3 1 4 1 D. [ 1 2 0 − 1 3 − 1 3 1 2 0 1 4 − 1 3 1 4 ] \begin{bmatrix}\frac{1}{2}&0&-\frac{1}{3}\\-\frac{1}{3}&\frac{1}{2}&0\\\frac{1}{4}&-\frac{1}{3}&\frac{1}{4}\end{bmatrix} 2 1 − 3 1 4 1 0 2 1 − 3 1 − 3 1 0 4 1
由向量α 1 = [ 1 , 0 , 1 ] T \alpha_1=[1,0,1]^T α 1 = [ 1 , 0 , 1 ] T ,α 2 = [ 1 , 2 , 3 ] T \alpha_2=[1,2,3]^T α 2 = [ 1 , 2 , 3 ] T ,α 3 = [ 2 , 2 , 4 ] T \alpha_3=[2,2,4]^T α 3 = [ 2 , 2 , 4 ] T 生成的向量空间V = s p a n { α 1 , α 2 , α 3 } = { k 1 α 1 + k 2 α 2 + k 3 α 3 ∣ k 1 , k 2 , k 3 ∈ R } V=span\{\alpha_1,\alpha_2,\alpha_3\}=\{k_1\alpha_1+k_2\alpha_2+k_3\alpha_3|k_1,k_2,k_3\in R\} V = s p an { α 1 , α 2 , α 3 } = { k 1 α 1 + k 2 α 2 + k 3 α 3 ∣ k 1 , k 2 , k 3 ∈ R } ,则V V V 的一个规范正交基为